JEE Main 2026 — Jan 21, Shift 1 — Chemistry solution

JEE Main2026Jan 21, Shift 1Chemistry

In Carius method, 0.75 g of an organic compound gave 1.2 g of barium sulphate. Find percentage of sulphur (molar mass 32 g mol $^{- 1}$ ). Molar mass of barium sulphate is 233 g mol $^{- 1}$ .

A
4.55%
B
10.30%
C
21.97%
D
16.48%

Solution

$% S = \frac{n _{B a S O_{4}} \times 32}{W _{co m p o u n d}} \times 100 = \frac{1.2 \times 32}{233} \times \frac{100}{0.75} = 21.97%$ .

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