JEE Main 2026 Jan 23 Shift 2, Chemistry Q15: Qualitative and Quantitative Analysis

JEE Main2026Jan 23, Shift 2Chemistry

In Carius method 0.2425 g of an organic compounds gave 0.5253 g silver chloride. The percentage of chlorine in the organic compound is

Solution

In the Carius method, all chlorine in the organic compound is converted to $A g C l$ (molar mass 143.5 g/mol; Cl contributes 35.5 g/mol).

$% of Cl = \frac{35.5}{143.5} \times \frac{mass of AgCl}{mass of compound} \times 100$

$= \frac{35.5}{143.5} \times \frac{0.5253}{0.2425} \times 100$

$\approx 0.2474 \times 2.166 \times 100 \approx 53.58%$ .

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