JEE Main 2026 — Jan 21, Shift 1 — Chemistry solution

JEE Main2026Jan 21, Shift 1Chemistry

An organic compound (P) on treatment with aqueous ammonia under hot condition forms compound (Q) which on heating with $B r_{2}$ and $K O H$ forms compound (R) having molecular formula $C_{6} H_{7} N$ . Names of P, Q and R respectively are:

A
Benzoic acid, benzamide, aniline
B
Toluic acid, methylbenzamide, 2-methylaniline
C
Benzoic acid, 4-methylbenzamide, 4-methylaniline
D
Phenylethanoic acid, phenylethanamide, benzamine

Solution

$P h - C O O H N H_{3}, Δ P h - C O N H_{2} B r_{2} / K O H P h - N H_{2}$ (Hofmann bromamide rearrangement).

$P h - N H_{2}$ is aniline with molecular formula $C_{6} H_{7} N$ .

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