JEE Main 2026 — Jan 24, Shift 2 — Chemistry solution

JEE Main2026Jan 24, Shift 2Chemistry

Given below are two statements :

Statement I : The dipole moment of R-CN is greater than R-NC and R-NC can undergo hydrolysis under acidic medium to produce $R - COOH$ .

Statement II : R-CN hydrolyses under acidic medium to produce a compound which on treatment with $SOCl_{2}$ , followed by the addition of $NH_{3}$ gives another compound (x). This compound (x) on treatment with NaOCl/NaOH gives a product, that on treatment with $CHCl_{3} / KOH /Δ$ produces R-NC.

In the light of the above statements, choose the correct answer from the options given below :

A
Both Statement I and Statement II are false
B
Both Statement I and Statement II are true
C
Statement I is true but Statement II is false
D
Statement I is false but Statement II is true

Solution

Statement I: Although R-CN does have a larger dipole moment than R-NC, the second part is wrong. Acidic hydrolysis of R-NC yields a primary amine and formic acid, not R-COOH:

$R - NC H_{3} O^{+} R - NH_{2} + HCOOH$

So Statement I is false.

Statement II: Trace the sequence starting from R-CN:

$R - CN H_{3} O^{+} RCOOH SOCl_{2} RCOCl NH_{3} RCONH_{2}$

$NaOCl / NaOH R - NH_{2} CHCl_{3} / KOH R - NC$ (carbylamine reaction)

Statement II is true.

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