JEE Main 2026 Jan 23 Shift 2, Chemistry Q6: Periodicity In Atomic Properties

JEE Main2026Jan 23, Shift 2Chemistry

Elements X and Y belong to Group 15. The difference between the electronegativity values of 'X' and phosphorus is higher than that of the difference between phosphorus and 'Y'. 'X' & 'Y' are respectively

A
N & As
B
As & Bi
C
Bi & N
D
As & Sb

Solution

Approximate electronegativity values in Group 15:

N $\approx$ 3.0, P $\approx$ 2.1, As $\approx$ 2.0, Sb $\approx$ 1.9, Bi $\approx$ 1.9

Take $X = N$ and $Y = A s$ :

$∣ E N (N) - E N (P) ∣ = ∣3.0 - 2.1∣ = 0.9$

$∣ E N (P) - E N (A s) ∣ = ∣2.1 - 2.0∣ = 0.1$

$0.9 > 0.1$ , so the condition is satisfied. $X = N$ , $Y = A s$ .

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JEE Main 2026 Jan 23 Shift 2, Chemistry Q6: Periodicity In Atomic Properties

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