JEE Main 2026 — Jan 23, Shift 2 — Chemistry solution

JEE Main2026Jan 23, Shift 2Chemistry

Identify the CORRECT set of details from the following :

A. $[C o (N H_{3})_{6}]^{3 +}$ : Inner orbital complex ; $d^{2} s p^{3}$ hybridized

B. $[M n C l_{6}]^{3 -}$ : Outer orbital complex; $s p^{3} d^{2}$ hybridized

C. $[C o F_{6}]^{3 -}$ : Outer orbital complex ; $d^{2} s p^{3}$ hybridized

D. $[F e F_{6}]^{3 -}$ : Outer orbital complex: $s p^{3} d^{2}$ hybridized

E. $[N i (C N)_{4}]^{2 -}$ : Inner orbital complex ; $s p^{3}$ hybridized

Choose the correct answer from the options given below:

A
C & D only
B
A, B & D only
C
A, C & E only
D
A, B, C, D & E

Solution

Check each entry against CFT/VBT rules:

(A) $C o^{3 +}$ is $d^{6}$ . $N H_{3}$ is a strong-field ligand, so electrons pair up giving $d^{2} s p^{3}$ inner orbital complex. Correct.

(B) $M n^{3 +}$ is $d^{4}$ . $C l^{-}$ is a weak-field ligand giving $s p^{3} d^{2}$ outer orbital complex. Correct.

(C) $C o^{3 +}$ is $d^{6}$ but $F^{-}$ is a weak-field ligand, so the complex is $s p^{3} d^{2}$ outer orbital, not $d^{2} s p^{3}$ . Incorrect.

(D) $F e^{3 +}$ is $d^{5}$ with weak-field $F^{-}$ , giving $s p^{3} d^{2}$ outer orbital complex. Correct.

(E) $N i^{2 +}$ is $d^{8}$ . With strong-field $C N^{-}$ and coordination number 4, the geometry is square planar with $d s p^{2}$ hybridization, not $s p^{3}$ . Incorrect.

Correct set: A, B and D.

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