Fundamentholfundamenthol
NEET2018Paper 2018Chemistry
Q.

The solubility of BaSO4 in water is 2.42 × 10–3 g L–1at 298 K. The value of its solubility product (Ksp) will be (Given molar mass of BaSO4= 233 g mol–1)

  1. A

    1.08 × 10–10 mol2 L–2

  2. B

    1.08 × 10–14 mol2 L–2

  3. C

    1.08 × 10–12 mol2 L–2

  4. D

    1.08 × 10–8 mol2 L–2

Solution

Practice more Chemistry

Concept-wise practice with instant solutions on Fundamenthol.

Start practicing →