NEET 2026 — Chemistry solution

NEET2026Chemistry

Identify the correct statements :

(A) The molality of 2.5 g of ethanoic acid (Molar mass : 60 g mol $^{- 1}$ ) in 75 g of benzene solution is 0.556 m.

(B) The molarity of a solution containing 5 g of NaOH (molar mass : 40 g mol $^{- 1}$ ) in 450 mL of solution is 0.278 M at 298 K.

(D) The solubility of gas increases with decrease in pressure.

(E) For a binary mixture of A and B, the number of moles of A and B are $n_{A}$ and $n_{B}$ respectively. The mole fraction of B will be $x_{B} = \frac{n _{A}}{n _{A} + n _{B}}$

Choose the correct answer from the options given below :

A
A, B and C only
B
A, D and E only
C
A and B only
D
A and C only

Solution

(A) Molality $= \frac{n _{so l u t e}}{w _{so l v e n t} ( kg )} = \frac{2.5/60}{0.075} \approx 0.556$ m. Correct.

(B) Molarity $= \frac{5/40}{0.450} = \frac{0.125}{0.450} \approx 0.278$ M. Correct.

(C) Gas solubility increases at lower temperature, so aquatic species are indeed more comfortable in cold water. Correct.

(D) Gas solubility increases with increase in pressure (Henry’s law), so D is incorrect.

(E) Mole fraction of B should be $x_{B} = \frac{n _{B}}{n _{A} + n _{B}}$ , so the given expression is incorrect.

Correct set: A, B and C.

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