NEET 2026 — Chemistry solution

NEET2026Chemistry

In a qualitative analysis, Bi $^{3 +}$ is detected by appearance of precipitate of BiO(OH)(s). Calculate pH when the following equilibrium exists at 298 K :

$B i O (O H) (s) ⇌ B i O^{+} (a q) + O H^{-} (a q), K = 4 \times 1 0^{- 10}$

(Given : log 2 = 0.3010)

A
4.699
B
5.286
C
8.714
D
9.301

Solution

Let solubility be $S$ . Then $[B i O^{+}] = [O H^{-}] = S$ , and $K_{s p} = S^{2} = 4 \times 1 0^{- 10}$ , giving $S = 2 \times 1 0^{- 5}$ M.

$[O H^{-}] = 2 \times 1 0^{- 5}$ , so $pO H = 5 - lo g 2 = 5 - 0.3010 = 4.699$ .

$p H = 14 - pO H = 14 - 4.699 = 9.301$ .

← Back to full paper

Practice more Chemistry

Concept-wise practice with instant solutions on Fundamenthol.

Start practicing →