NEET 2026 — Chemistry solution

NEET2026Chemistry

The number of hydrogen atoms present in 5.4 g of urea is :

(Given : Molar mass of urea: 60 g mol $^{- 1}$ , N $_{A} = 6.022 \times 1 0^{23}$ particles mol $^{- 1}$ )

Solution

Urea = NH $_{2}$ CONH $_{2}$ contains 4 H atoms per molecule.

Moles of urea = $5.4/60 = 0.09$ mol; moles of H atoms = $0.09 \times 4 = 0.36$ mol.

Number of H atoms = $0.36 \times 6.022 \times 1 0^{23} \approx 2.168 \times 1 0^{23}$ .

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