NEET 2024 — Chemistry solution

NEET2024Chemistry

1 gram of sodium hydroxide was treated with 25 mL of 0.75 M HCl solution, the mass of sodium hydroxide left unreacted is equal to

Solution

Moles of NaOH initially $= 1/40 = 0.025$ mol.

Moles of HCl $= 0.025 L \times 0.75 = 0.01875$ mol.

Reaction is 1:1, so NaOH unreacted $= 0.025 - 0.01875 = 0.00625$ mol $= 0.00625 \times 40 = 0.25$ g $= 250$ mg.

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