NEET2019Paper 2019Physics
Q.
An electron is accelerated through a potential difference of 10,000 V. Its de Broglie wavelength is, (nearly) : (me = 9 × 10–31 kg)
- A
12.2 × 10–13 m
- B
12.2 × 10–12 m
- C
12.2 × 10–14 m
- D
12.2 nm
Solution

Practice more Physics
Concept-wise practice with instant solutions on Fundamenthol.
Start practicing →