NEET 2024 — Physics solution

NEET2024Physics

The graph which shows the variation of $\frac{1}{λ ^{2}}$ and its kinetic energy, $E$ is (where $λ$ is de Broglie wavelength of a free particle):

Solution

$λ = \frac{h}{2 m E} \Rightarrow \frac{1}{λ ^{2}} = \frac{2 m E}{h ^{2}}$ .

This is linear in $E$ with positive slope and passes through the origin.

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