NEET2019Paper 2019Chemistry
Q.
Under isothermal condition, a gas at 300 K expands from 0.1 L to 0.25 L against a constant external pressure of 2 bar. The work done by the gas is (Given that 1 L bar = 100 J)
- A
–30 J
- B
5 kJ
- C
25 J
- D
30 J
Solution
Wirr = – Pext V
= – 2 bar × (0.25 – 0.1) L
= – 2 × 0.15 L-bar
= – 0.30 L-bar
= – 0.30 × 100 J
= – 30 J
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