NEET 2024 — Chemistry solution

NEET2024Chemistry

The work done during reversible isothermal expansion of one mole of hydrogen gas at 25 $^{\circ}$ C from pressure of 20 atmosphere to 10 atmosphere is: (Given $R = 2.0$ cal K $^{- 1}$ mol $^{- 1}$ )

A
413.14 calories
B
100 calories
C
0 calorie
D
$- 413.14$ calories

Solution

For isothermal reversible expansion of an ideal gas: $W = - n R T ln \frac{P _{1}}{P _{2}}$ .

$W = - (1) (2) (298) ln (20/10) = - 596 \times 0.6931 \approx - 413.14$ cal.

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