Fundamentholfundamenthol
NEET2022Physics
Q.

An electric lift with a maximum load of 2000 kg (lift + passengers) is moving up with a constant speed of 1.5 ms. The frictional force opposing the motion is 3000 N. The minimum power delivered by the motor to the lift in watts is : (g = 10 ms)

  1. A

    20000

  2. B

    34500

  3. C

    23500

  4. D

    23000

Solution

Constant velocity means zero net force, so the upward tension equals the sum of weight and friction.

N.

Power delivered: W.

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