NEET 2022 — Chemistry solution

NEET2022Chemistry

Match List-I with List-II

	List-I (Hydrides)		List-II (Nature)
(a)	MgH $_{2}$	(i)	Electron precise
(b)	GeH $_{4}$	(ii)	Electron deficient
(c)	B $_{2}$ H $_{6}$	(iii)	Electron rich
(d)	HF	(iv)	Ionic

Choose the correct answer from the options given below :

A
(a)-(iii), (b)-(i), (c)-(ii), (d)-(iv)
B
(a)-(i), (b)-(ii), (c)-(iv), (d)-(iii)
C
(a)-(ii), (b)-(iii), (c)-(iv), (d)-(i)
D
(a)-(iv), (b)-(i), (c)-(ii), (d)-(iii)

Solution

Classify each hydride by the relation between its bonding electrons and the number of bonds it needs.

MgH $_{2}$ is a saline (ionic) hydride formed by an active metal, matching (iv).

GeH $_{4}$ has just enough electrons to form four two-centre two-electron bonds with no lone pairs, so it is electron precise, matching (i).

B $_{2}$ H $_{6}$ has fewer valence electrons than required for normal 2c-2e bonds and uses 3c-2e banana bonds, making it electron deficient, matching (ii).

HF has lone pairs on the central atom over and above its bonding electrons, classifying it as electron rich, matching (iii).

← Back to full paper

Practice more Chemistry

Concept-wise practice with instant solutions on Fundamenthol.

Start practicing →