Given below are two statements : -
Statement I :
The boiling points of aldehydes and ketones are higher than hydrocarbons of comparable molecular masses because of weak molecular association in aldehydes and ketones due to dipole-dipole interactions.
Statements II :
The boiling points aldehydes and ketones are lower than the alcohols of similar molecular masses due to the absence of H-bonding.
In the light of the statements, choose the most appropriate answer from the options given below :
- A
Both statements I and statements II are incorrect.
- B
Statement I is correct but statements II is incorrect
- C
Statements I is incorrect but statements II is correct.
- D
Both statements I and statements li are correct.
For molecules of comparable molar mass, the trend in boiling points is alcohol aldehyde or ketone hydrocarbon.
Aldehydes and ketones have polar C=O groups that participate in dipole-dipole attractions, which a non-polar hydrocarbon lacks. So Statement I is correct.
Alcohols additionally form intermolecular hydrogen bonds (O-H to O), an interaction unavailable to carbonyl compounds, so alcohols boil higher than the corresponding aldehydes and ketones. Statement II is correct as well.
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