NEET 2023 — Physics solution

NEET2023Physics

The ratio of frequencies of fundamental harmonic produced by an open pipe to that of closed pipe having the same length is:

Solution

Fundamental frequency of an open pipe: $n_{o p e n} = \frac{v}{2 L}$ .

Fundamental frequency of a closed pipe: $n_{c l ose d} = \frac{v}{4 L}$ .

Ratio $\frac{n _{o p e n}}{n _{c l ose d}} = \frac{v /2 L}{v /4 L} = 2 : 1$ .

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