NEET 2025 — Physics solution

NEET2025Physics

A pipe open at both ends has a fundamental frequency $f$ in air. The pipe is now dipped vertically in a water drum to half of its length. The fundamental frequency of the air column is now equal to:

A
$\frac{f}{2}$
B
$f$
C
$\frac{3 f}{2}$
D
$2 f$

Solution

Open pipe of length $ℓ$ : fundamental $f = \frac{V}{2 ℓ}$ .

When half is dipped, the air column is now a closed-open pipe (CoP) of length $ℓ /2$ : fundamental $f^{'} = \frac{V}{4 ( ℓ /2 )} = \frac{V}{2 ℓ} = f$ .

$∴ f^{'} = f$ .

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