NEET 2023 — Physics solution

NEET2023Physics

The magnetic energy stored in an inductor of inductance $4 μ H$ carrying a current of $2$ A is:

Solution

Energy stored in an inductor: $U = \frac{1}{2} L i^{2}$ .

With $L = 4 \times 1 0^{- 6}$ H and $i = 2$ A:

$U = \frac{1}{2} \times 4 \times 1 0^{- 6} \times 4 = 8 \times 1 0^{- 6}$ J $= 8 μ J$ .

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