NEET 2023, Chemistry Q33: Carboxylic Acid Derivatives

NEET2023Chemistry

Weight (g) of two moles of the organic compound, which is obtained by heating sodium ethanoate with sodium hydroxide in presence of calcium oxide is:

Solution

This is decarboxylation (soda-lime reaction):

$CH_{3} COONa + NaOH CaO, Δ CH_{4} + Na_{2} CO_{3}$

The organic product is methane ( $M = 16$ g/mol).

For 2 moles: $2 \times 16 = 32$ g.

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