NEET 2024 — Physics solution

NEET2024Physics

The maximum elongation of a steel wire of 1 m length if the elastic limit of steel and its Young's modulus, respectively, are $8 \times 1 0^{8}$ Nm $^{- 2}$ and $2 \times 1 0^{11}$ Nm $^{- 2}$ , is:

A
40 mm
B
8 mm
C
4 mm
D
0.4 mm

Solution

From $Y = \frac{stress}{strain}$ , max strain $= \frac{σ _{m a x}}{Y} = \frac{8 \times 1 0 ^{8}}{2 \times 1 0 ^{11}} = 4 \times 1 0^{- 3}$ .

Max elongation $= strain \times L = 4 \times 1 0^{- 3} \times 1 = 4 \times 1 0^{- 3}$ m $= 4$ mm.

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