NEET 2024 — Physics solution

NEET2024Physics

A wire of length ' $l$ ' and resistance 100 $Ω$ is divided into 10 equal parts. The first 5 parts are connected in series while the next 5 parts are connected in parallel. The two combinations are again connected in series. The resistance of this final combination is:

A
55 $Ω$
B
60 $Ω$
C
26 $Ω$
D
52 $Ω$

Solution

Each piece has $R = 100/10 = 10 Ω$ .

Series of 5: $R_{s} = 5 \times 10 = 50 Ω$ .

Parallel of 5: $R_{p} = 10/5 = 2 Ω$ .

These two in series: $R = 50 + 2 = 52 Ω$ .

← Back to full paper

Practice more Physics

Concept-wise practice with instant solutions on Fundamenthol.

Start practicing →