NEET 2024 — Physics solution

NEET2024Physics

The terminal voltage of the battery, whose emf is 10 V and internal resistance 1 $Ω$ , when connected through an external resistance of 4 $Ω$ as shown in the figure is:

A
8 V
B
10 V
C
4 V
D
6 V

Solution

Current $I = \frac{E}{R + r} = \frac{10}{4 + 1} = 2$ A.

Terminal voltage $V = E - I r = 10 - 2 \times 1 = 8$ V.

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