NEET 2025, Physics Q10: Work Energy Theorem And Its Applications

NEET2025Physics

A ball of mass $0.5$ kg is dropped from a height of $40$ m. The ball hits the ground and rises to a height of $10$ m. The impulse imparted to the ball during its collision with the ground is (take $g = 9.8$ m/s $^{2}$ ):

A
21 NS
B
7 NS
C
0
D
84 NS

Solution

Velocity just before impact (downward, taken negative): $v_{i} = - 2 g h_{1} = - 2 \times 9.8 \times 40 = - 28$ m/s.

Velocity just after impact (upward): $v_{f} = + 2 g h_{2} = + 2 \times 9.8 \times 10 = 14$ m/s.

Impulse $J = Δ p = m (v_{f} - v_{i}) = 0.5 \times (14 - (- 28)) = 0.5 \times 42 = 21$ NS.

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NEET 2025, Physics Q10: Work Energy Theorem And Its Applications

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