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NEET2025Chemistry
Q.

Which one of the following compounds can exist as cis-trans isomers?

  1. A

    Pent-1-ene

  2. B

    2-Methylhex-2-ene

  3. C

    1,1-Dimethylcyclopropane

  4. D

    1,2-Dimethylcyclohexane

Solution

Geometrical isomerism (cis/trans) requires two different groups on each of the carbons involved in the restricted-rotation feature (double bond or ring).

Pent-1-ene: terminal alkene, one end has two H's — no cis/trans.

2-Methylhex-2-ene: one of the double-bond carbons carries two identical methyl groups — no cis/trans.

1,1-Dimethylcyclopropane: both methyl groups are on the same carbon — no cis/trans.

1,2-Dimethylcyclohexane: the two methyls are on adjacent ring carbons, each ring carbon also bears an H — these two substituents can be on the same face (cis) or opposite faces (trans).

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