Which one of the following compounds can exist as cis-trans isomers?
- A
Pent-1-ene
- B
2-Methylhex-2-ene
- C
1,1-Dimethylcyclopropane
- D
1,2-Dimethylcyclohexane


Geometrical isomerism (cis/trans) requires two different groups on each of the carbons involved in the restricted-rotation feature (double bond or ring).
Pent-1-ene: terminal alkene, one end has two H's — no cis/trans.
2-Methylhex-2-ene: one of the double-bond carbons carries two identical methyl groups — no cis/trans.
1,1-Dimethylcyclopropane: both methyl groups are on the same carbon — no cis/trans.
1,2-Dimethylcyclohexane: the two methyls are on adjacent ring carbons, each ring carbon also bears an H — these two substituents can be on the same face (cis) or opposite faces (trans).
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