NEET 2026 — Physics solution

NEET2026Physics

The angular speed of a flywheel is increased from 600 rpm to 1200 rpm in 10 s. The number of revolutions completed by the flywheel during this time is :

A
600
B
300
C
900
D
150

Solution

Convert to rad/s: $ω_{i} = 600$ rpm $= 20 π$ rad/s and $ω_{f} = 1200$ rpm $= 40 π$ rad/s, with $t = 10$ s.

For uniform angular acceleration, the angle swept is

$θ = (\frac{ω _{i} + ω _{f}}{2}) t = (\frac{40 π + 20 π}{2}) \times 10 = 300 π$ rad.

Number of revolutions $= \frac{θ}{2 π} = \frac{300 π}{2 π} = 150$ .

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