NEET 2026 — Physics solution

NEET2026Physics

An unknown nucleus has a nuclear density of $2.29 \times 1 0^{17}$ kg/m $^{3}$ and mass of $19.926 \times 1 0^{- 27}$ kg. Its mass number A is approximately :

(Take $R_{0} = 1.2 \times 1 0^{- 15}$ m, $4 π = 12.56$ )

A
16
B
20
C
12
D
19

Solution

Mass = Volume $\times$ Density, and $R = R_{0} A^{1/3}$ .

$M = \frac{4}{3} π R_{0}^{3} A \cdot ρ$

$A = \frac{3 M}{4 π R _{0}^{3} ρ}$

$A = \frac{3 \times 19.926 \times 1 0 ^{- 27}}{12.56 \times ( 1.2 \times 1 0 ^{- 15} ) ^{3} \times 2.29 \times 1 0 ^{17}} = 12$ .

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