NEET 2026 — Chemistry solution

NEET2026Chemistry

When 1 dm $^{3}$ of CO $_{2}$ gas is passed over hot coke, the volume of gaseous mixture after complete reaction at STP becomes 1.4 dm $^{3}$ . The composition of the gaseous mixture at STP is :

A
0.6 dm $^{3}$ of CO, 0.8 dm $^{3}$ of CO $_{2}$
B
0.8 dm $^{3}$ of CO, 0.8 dm $^{3}$ of CO $_{2}$
C
0.6 dm $^{3}$ of CO, 0.4 dm $^{3}$ of CO $_{2}$
D
0.8 dm $^{3}$ of CO, 0.6 dm $^{3}$ of CO $_{2}$

Solution

Reaction: $C O_{2} (g) + C (s) \to 2 C O (g)$

Let $x$ dm $^{3}$ of CO $_{2}$ react. Then CO formed = $2 x$ and CO $_{2}$ left = $1 - x$ .

Total volume: $(1 - x) + 2 x = 1 + x = 1.4$ , so $x = 0.4$ .

$V_{C O} = 2 x = 0.8$ dm $^{3}$ ; $V_{C O_{2}} = 1 - x = 0.6$ dm $^{3}$ .

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