JEE Main 2025 Apr 2 Shift 2, Physics Q13: Logic Gates

Propagating the two input $1$s through each gate in turn (using standard truth tables for the inverter, AND with negated output bubbles and NOR-like elements drawn in the circuit) yields intermediate signals that combine to give $0$ at both final outputs.

Working through the upper branch of the network: both inputs are $1$, so the first stage produces $1$, the next stage inverts it to $0$, and the AND with another $0$ branch gives $P=0$.

For the lower branch, the inverters convert the $1$ inputs to $0$, which then feed a NOR-style combination that outputs $0$, giving $Q=0$.

$\therefore P=0$ and $Q=0$.