NEET 2022, Chemistry Q35: Law of Chemical Equilibrium And Equilibrium Constant

NEET2022Chemistry

3O $_{2}$ (g) $⇌$ 2O $_{3}$ (g)

for the above reaction at 298 K, K $_{C}$ is found to be 3.0 $\times$ 10 $^{- 59}$ . If the concentration of O $_{2}$ at equilibrium is 0.040 M then concentration of O $_{3}$ in M is

A
$1.9 \times 1 0^{- 63}$
B
$2.4 \times 1 0^{31}$
C
$1.2 \times 1 0^{21}$
D
$4.38 \times 1 0^{- 32}$

Solution

Equilibrium expression: $K_{c} = \frac{[ O _{3} ] ^{2}}{[ O _{2} ] ^{3}}$ .

$[O_{3}]^{2} = K_{c} \times [O_{2}]^{3} = 3.0 \times 1 0^{- 59} \times (4 \times 1 0^{- 2})^{3}$ .

$(4 \times 1 0^{- 2})^{3} = 64 \times 1 0^{- 6}$ , so $[O_{3}]^{2} = 3.0 \times 1 0^{- 59} \times 64 \times 1 0^{- 6} = 192 \times 1 0^{- 65} = 1.92 \times 1 0^{- 63}$ .

$[O_{3}] = 1.92 \times 1 0^{- 63} \approx 4.38 \times 1 0^{- 32}$ M.

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NEET 2022, Chemistry Q35: Law of Chemical Equilibrium And Equilibrium Constant

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