NEET 2023 — Physics solution

NEET2023Physics

A horizontal bridge is built across a river. A student standing on the bridge throws a small ball vertically upwards with a velocity $4$ m s $^{- 1}$ . The ball strikes the water surface after $4$ s. The height of bridge above water surface is (Take $g = 10$ m s $^{- 2}$ ):

A
$60$ m
B
$64$ m
C
$68$ m
D
$56$ m

Solution

Take downward as positive and let $H$ be the bridge height. Initial velocity is $- 4$ m/s (upward) and acceleration is $+ 10$ m/s $^{2}$ .

$H = - u t + \frac{1}{2} g t^{2} = - 4 \times 4 + \frac{1}{2} \times 10 \times 16 = - 16 + 80 = 64$ m.

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