NEET 2024, Physics Q43: SHM in Pendulums

NEET2024Physics

If the mass of the bob in a simple pendulum is increased to thrice its original mass and its length is made half its original length, then the new time period of oscillation is $\frac{x}{2}$ times its original time period. Then the value of $x$ is

A
$23$
B
4
C
3
D
$2$

Solution

$T = 2 π l / g$ does not depend on mass.

With length halved: $T^{'} = 2 π l / (2 g) = \frac{T}{2}$ .

Set $\frac{x}{2} T = \frac{T}{2} \Rightarrow x = \frac{2}{2} = 2$ .

Concept behind this question

SHM in PendulumsNotes, formulas and examples →

Practice more Physics

Concept-wise practice with instant solutions on Fundamenthol.

Start practicing →

NEET 2024, Physics Q43: SHM in Pendulums

Concept behind this question

More previous year questions on SHM in Pendulums

Practice more Physics