NEET 2026, Physics Q1: SHM in Pendulums

The kinetic energy of a simple pendulum is

$K.E=\frac{1}{2}m{\omega }^2{A}^2{\cos }^2\omega t$ (when oscillation starts from the extreme position).

Since K.E is proportional to ${\cos }^2\omega t$, it is always non-negative and touches zero at the extreme positions ($t=0,T/2,T$), giving two positive humps per period. This matches option (4).