NEET 2026 — Physics solution

NEET2026Physics

Savitha, a XI standard student, while conducting an experiment to determine the effective length of a simple pendulum L, notes down the data of time taken to complete 30 oscillations as 60 s and hence calculates the length of the simple pendulum as :

(Take $π^{2} = 9.8$ , and g = 9.8 m/s $^{2}$ )

A
0.75 m
B
1 m
C
1.5 m
D
2 m

Solution

Time period $T = 60/30 = 2$ s.

$T = 2 π \frac{ℓ}{g}$

$2 = 2 π \frac{ℓ}{π ^{2}}$ (since $g = π^{2}$ )

$\frac{1}{π} = \frac{ℓ}{π ^{2}}$

$ℓ \approx 1$ m.

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