NEET 2026, Physics Q36: Semiconductors, p-n Junction Diode and Applications

Diodes $D_1$ and $D_3$ are forward biased (closed switches); $D_2$ and $D_4$ are reverse biased (open). So only the 4 $\Omega$ and 2 $\Omega$ branches conduct.

These two branches are in parallel:

$R_{eq}=\frac{4\times 2}{4+2}=\frac{4}{3}\Omega$

$I=\frac{V}{R_{eq}}=\frac{10}{4/3}=\frac{15}{2}$ A.