JEE Main 2026 Apr 5 Shift 2, Chemistry Q22: Introduction to Mechanism of Organic Reaction

JEE Main2026Apr 5, Shift 2Chemistry

$R M g I$ when treated with ice cold water liberated a gas which occupied 1.4 dm $^{3}$ /g at STP. The gas produced is further reacted with iodine in presence of $H I O_{3}$ to give compound (X). Compound (X) in presence of Na and dry ether produced compound (Y). Molar mass of compound (Y) is ____ g mol $^{- 1}$ . (Nearest integer)

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Solution

From 1.4 dm $^{3}$ /g at STP (using 22.4 L/mol): molar mass of gas $= 22.4/1.4 = 16$ g/mol $\Rightarrow$ gas is $C H_{4}$ . Hence $R = C H_{3}$ .

$C H_{3} M g I + H_{2} O \to C H_{4} + M g (O H) I$ .

$C H_{4} + I_{2} H I O_{3} C H_{3} I$ (compound X).

$2 C H_{3} I + 2 N a dry ether C H_{3} - C H_{3} + 2 N a I$ (Wurtz reaction). Compound Y is ethane.

Molar mass of ethane $= 2 (12) + 6 (1) = 30$ g/mol.

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JEE Main 2026 Apr 5 Shift 2, Chemistry Q22: Introduction to Mechanism of Organic Reaction

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