NEET 2022 — Chemistry solution

NEET2022Chemistry

A 10.0 L flask contains 64 g of oxygen at 27 $^{\circ}$ C. (Assume O $_{2}$ gas is behaving ideally). The pressure inside the flask in bar is

(Given R = 0.0831 L bar K $^{- 1}$ mol $^{- 1}$ )

Solution

Moles of O $_{2}$ : $n = \frac{64}{32} = 2$ mol.

Temperature: $T = 27 + 273 = 300$ K.

Ideal gas law: $P = \frac{n R T}{V} = \frac{2 \times 0.0831 \times 300}{10} = \frac{49.86}{10} \approx 4.9$ bar.

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