JEE Main 2026 Jan 23 Shift 2, Physics Q13: Logic Gates

JEE Main2026Jan 23, Shift 2Physics

For the given logic gate circuit, which of the following is the correct truth table?

Solution

Let $X = n + m$ (output of OR gate). Then $z = \overline{n \cdot X} = \overline{n \cdot (n + m)}$ .

Using absorption: $n \cdot (n + m) = n$ (since $n + nm = n$ ).

$∴ z = \overline{n}$ , depending only on $n$ .

Truth table: $n = 0 \Rightarrow z = 1$ ; $n = 1 \Rightarrow z = 0$ (regardless of $m$ ).

Matches option (4).

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